Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101011101010100100001 |
3 | 10220011022121001001212001 |
4 | 100000131231131110201 |
5 | 121010310040133432 |
6 | 2201200533404001 |
7 | 142321163302564 |
oct | 20003555352441 |
9 | 3804277031761 |
10 | 1100010083617 |
11 | 39456a018a65 |
12 | 159233199601 |
13 | 7c965bc8c03 |
14 | 3b3529704db |
15 | 1d9317e39e7 |
hex | 1001db5d521 |
1100010083617 has 2 divisors, whose sum is σ = 1100010083618. Its totient is φ = 1100010083616.
The previous prime is 1100010083591. The next prime is 1100010083633. The reversal of 1100010083617 is 7163800100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 820384874001 + 279625209616 = 905751^2 + 528796^2 .
It is a cyclic number.
It is not a de Polignac number, because 1100010083617 - 27 = 1100010083489 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100010053617) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005041808 + 550005041809.
It is an arithmetic number, because the mean of its divisors is an integer number (550005041809).
Almost surely, 21100010083617 is an apocalyptic number.
It is an amenable number.
1100010083617 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010083617 is an equidigital number, since it uses as much as digits as its factorization.
1100010083617 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 1008, while the sum is 28.
Adding to 1100010083617 its reverse (7163800100011), we get a palindrome (8263810183628).
The spelling of 1100010083617 in words is "one trillion, one hundred billion, ten million, eighty-three thousand, six hundred seventeen".
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