Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …101111010000000010011 |
3 | 10220011022121021001000112 |
4 | 100000131231322000103 |
5 | 121010310102413412 |
6 | 2201200540111535 |
7 | 142321164302246 |
oct | 20003555720023 |
9 | 3804277231015 |
10 | 1100010201107 |
11 | 39456a099264 |
12 | 1592332355ab |
13 | 7c965c3a52c |
14 | 3b3529a125d |
15 | 1d931818722 |
hex | 1001db7a013 |
1100010201107 has 2 divisors, whose sum is σ = 1100010201108. Its totient is φ = 1100010201106.
The previous prime is 1100010201077. The next prime is 1100010201131. The reversal of 1100010201107 is 7011020100011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100010201107 - 210 = 1100010200083 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 1100010201091 and 1100010201100.
It is not a weakly prime, because it can be changed into another prime (1100010201187) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005100553 + 550005100554.
It is an arithmetic number, because the mean of its divisors is an integer number (550005100554).
Almost surely, 21100010201107 is an apocalyptic number.
1100010201107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010201107 is an equidigital number, since it uses as much as digits as its factorization.
1100010201107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 1100010201107 its reverse (7011020100011), we get a palindrome (8111030301118).
The spelling of 1100010201107 in words is "one trillion, one hundred billion, ten million, two hundred one thousand, one hundred seven".
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