11000102083 has 2 divisors, whose sum is σ = 11000102084. Its totient is φ = 11000102082.

The previous prime is 11000102063. The next prime is 11000102089. The reversal of 11000102083 is 38020100011.

11000102083 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is an emirp because it is prime and its reverse (38020100011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000102083 - 2⁵ = 11000102051 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000102089) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500051041 + 5500051042.

It is an arithmetic number, because the mean of its divisors is an integer number (5500051042).

Almost surely, 2^11000102083 is an apocalyptic number.

11000102083 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000102083 is an equidigital number, since it uses as much as digits as its factorization.

11000102083 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 48, while the sum is 16.

Adding to 11000102083 its reverse (38020100011), we get a palindrome (49020202094).

The spelling of 11000102083 in words is "eleven billion, one hundred two thousand, eighty-three".