Base | Representation |
---|---|
bin | 10000000000011101101… |
… | …110000100000001010011 |
3 | 10220011022121100010021221 |
4 | 100000131232010001103 |
5 | 121010310110222011 |
6 | 2201200541025511 |
7 | 142321164532663 |
oct | 20003556040123 |
9 | 3804277303257 |
10 | 1100010242131 |
11 | 39456a117069 |
12 | 159233255297 |
13 | 7c965c530c8 |
14 | 3b3529b21a3 |
15 | 1d931825971 |
hex | 1001db84053 |
1100010242131 has 2 divisors, whose sum is σ = 1100010242132. Its totient is φ = 1100010242130.
The previous prime is 1100010242117. The next prime is 1100010242143. The reversal of 1100010242131 is 1312420100011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100010242131 - 219 = 1100009717843 is a prime.
It is a super-2 number, since 2×11000102421312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100010242431) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005121065 + 550005121066.
It is an arithmetic number, because the mean of its divisors is an integer number (550005121066).
Almost surely, 21100010242131 is an apocalyptic number.
1100010242131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100010242131 is an equidigital number, since it uses as much as digits as its factorization.
1100010242131 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1100010242131 its reverse (1312420100011), we get a palindrome (2412430342142).
The spelling of 1100010242131 in words is "one trillion, one hundred billion, ten million, two hundred forty-two thousand, one hundred thirty-one".
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