11000103213331 has 2 divisors, whose sum is σ = 11000103213332. Its totient is φ = 11000103213330.

The previous prime is 11000103213313. The next prime is 11000103213343. The reversal of 11000103213331 is 13331230100011.

Together with previous prime (11000103213313) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000103213331 - 2¹⁷ = 11000103082259 is a prime.

It is a super-2 number, since 2×11000103213331² (a number of 27 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000103213299 and 11000103213308.

It is not a weakly prime, because it can be changed into another prime (11000103213731) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500051606665 + 5500051606666.

It is an arithmetic number, because the mean of its divisors is an integer number (5500051606666).

Almost surely, 2^{11000103213331} is an apocalyptic number.

11000103213331 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000103213331 is an equidigital number, since it uses as much as digits as its factorization.

11000103213331 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 11000103213331 its reverse (13331230100011), we get a palindrome (24331333313342).

The spelling of 11000103213331 in words is "eleven trillion, one hundred three million, two hundred thirteen thousand, three hundred thirty-one".