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110001101101097 is a prime number
BaseRepresentation
bin11001000000101110100000…
…100011100101100000101001
3112102111000001212110111212012
4121000232200203211200221
5103404224223340213342
61025541450324125305
732112213554650043
oct3100564043454051
9472430055414765
10110001101101097
11320602289377a8
1210406b4a236835
13494c0a044937b
141d24120288a93
15cab5ab214b82
hex640ba08e5829

110001101101097 has 2 divisors, whose sum is σ = 110001101101098. Its totient is φ = 110001101101096.

The previous prime is 110001101101093. The next prime is 110001101101109. The reversal of 110001101101097 is 790101101100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 101734073041561 + 8267028059536 = 10086331^2 + 2875244^2 .

It is a cyclic number.

It is not a de Polignac number, because 110001101101097 - 22 = 110001101101093 is a prime.

It is not a weakly prime, because it can be changed into another prime (110001101101093) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000550550548 + 55000550550549.

It is an arithmetic number, because the mean of its divisors is an integer number (55000550550549).

Almost surely, 2110001101101097 is an apocalyptic number.

It is an amenable number.

110001101101097 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001101101097 is an equidigital number, since it uses as much as digits as its factorization.

110001101101097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 63, while the sum is 23.

The spelling of 110001101101097 in words is "one hundred ten trillion, one billion, one hundred one million, one hundred one thousand, ninety-seven".