110001111002113 has 2 divisors, whose sum is σ = 110001111002114. Its totient is φ = 110001111002112.

The previous prime is 110001111002087. The next prime is 110001111002147. The reversal of 110001111002113 is 311200111100011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 106844121190849 + 3156989811264 = 10336543^2 + 1776792^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-110001111002113 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 110001111002093 and 110001111002102.

It is not a weakly prime, because it can be changed into another prime (110001111002813) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000555501056 + 55000555501057.

It is an arithmetic number, because the mean of its divisors is an integer number (55000555501057).

Almost surely, 2^{110001111002113} is an apocalyptic number.

It is an amenable number.

110001111002113 is a deficient number, since it is larger than the sum of its proper divisors (1).

110001111002113 is an equidigital number, since it uses as much as digits as its factorization.

110001111002113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6, while the sum is 13.

Adding to 110001111002113 its reverse (311200111100011), we get a palindrome (421201222102124).

The spelling of 110001111002113 in words is "one hundred ten trillion, one billion, one hundred eleven million, two thousand, one hundred thirteen".