Base | Representation |
---|---|
bin | 1010000000010010100110… |
… | …1101101111010011100001 |
3 | 1102221121012122201012102221 |
4 | 2200010221231233103201 |
5 | 2420211211420214103 |
6 | 35221214204511041 |
7 | 2213506002422356 |
oct | 240045155572341 |
9 | 42847178635387 |
10 | 11000111101153 |
11 | 3561136a42949 |
12 | 1297a8ab4b481 |
13 | 61a3c9453695 |
14 | 2a05a021662d |
15 | 1412113031bd |
hex | a0129b6f4e1 |
11000111101153 has 2 divisors, whose sum is σ = 11000111101154. Its totient is φ = 11000111101152.
The previous prime is 11000111101103. The next prime is 11000111101159. The reversal of 11000111101153 is 35110111100011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8825040665809 + 2175070435344 = 2970697^2 + 1474812^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000111101153 - 217 = 11000110970081 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000111101159) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500055550576 + 5500055550577.
It is an arithmetic number, because the mean of its divisors is an integer number (5500055550577).
Almost surely, 211000111101153 is an apocalyptic number.
It is an amenable number.
11000111101153 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000111101153 is an equidigital number, since it uses as much as digits as its factorization.
11000111101153 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 15, while the sum is 16.
Adding to 11000111101153 its reverse (35110111100011), we get a palindrome (46110222201164).
The spelling of 11000111101153 in words is "eleven trillion, one hundred eleven million, one hundred one thousand, one hundred fifty-three".
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