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11000111101153 is a prime number
BaseRepresentation
bin1010000000010010100110…
…1101101111010011100001
31102221121012122201012102221
42200010221231233103201
52420211211420214103
635221214204511041
72213506002422356
oct240045155572341
942847178635387
1011000111101153
113561136a42949
121297a8ab4b481
1361a3c9453695
142a05a021662d
151412113031bd
hexa0129b6f4e1

11000111101153 has 2 divisors, whose sum is σ = 11000111101154. Its totient is φ = 11000111101152.

The previous prime is 11000111101103. The next prime is 11000111101159. The reversal of 11000111101153 is 35110111100011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 8825040665809 + 2175070435344 = 2970697^2 + 1474812^2 .

It is a cyclic number.

It is not a de Polignac number, because 11000111101153 - 217 = 11000110970081 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000111101159) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500055550576 + 5500055550577.

It is an arithmetic number, because the mean of its divisors is an integer number (5500055550577).

Almost surely, 211000111101153 is an apocalyptic number.

It is an amenable number.

11000111101153 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000111101153 is an equidigital number, since it uses as much as digits as its factorization.

11000111101153 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 15, while the sum is 16.

Adding to 11000111101153 its reverse (35110111100011), we get a palindrome (46110222201164).

The spelling of 11000111101153 in words is "eleven trillion, one hundred eleven million, one hundred one thousand, one hundred fifty-three".