Base | Representation |
---|---|
bin | 10000000000011101110… |
… | …001101101111001101011 |
3 | 10220011022200010210101112 |
4 | 100000131301231321223 |
5 | 121010310331400412 |
6 | 2201201013340535 |
7 | 142321205632631 |
oct | 20003561557153 |
9 | 3804280123345 |
10 | 1100011200107 |
11 | 39456a710886 |
12 | 15923363774b |
13 | 7c9661ca161 |
14 | 3b352b81351 |
15 | 1d931964722 |
hex | 1001dc6de6b |
1100011200107 has 2 divisors, whose sum is σ = 1100011200108. Its totient is φ = 1100011200106.
The previous prime is 1100011200089. The next prime is 1100011200133. The reversal of 1100011200107 is 7010021100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100011200107 - 28 = 1100011199851 is a prime.
It is a super-3 number, since 3×11000112001073 (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 1100011200091 and 1100011200100.
It is not a weakly prime, because it can be changed into another prime (1100011200007) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550005600053 + 550005600054.
It is an arithmetic number, because the mean of its divisors is an integer number (550005600054).
Almost surely, 21100011200107 is an apocalyptic number.
1100011200107 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100011200107 is an equidigital number, since it uses as much as digits as its factorization.
1100011200107 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 14, while the sum is 14.
Adding to 1100011200107 its reverse (7010021100011), we get a palindrome (8110032300118).
The spelling of 1100011200107 in words is "one trillion, one hundred billion, eleven million, two hundred thousand, one hundred seven".
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