Base | Representation |
---|---|
bin | 10000000000011101110… |
… | …001110010110011110100 |
3 | 10220011022200011210222011 |
4 | 100000131301302303310 |
5 | 121010310333021322 |
6 | 2201201014014004 |
7 | 142321206045352 |
oct | 20003561626364 |
9 | 3804280153864 |
10 | 1100011220212 |
11 | 39456a7249a3 |
12 | 159233647304 |
13 | 7c966206358 |
14 | 3b352b887d2 |
15 | 1d93196a677 |
hex | 1001dc72cf4 |
1100011220212 has 12 divisors (see below), whose sum is σ = 1969787534176. Its totient is φ = 537214781880.
The previous prime is 1100011220183. The next prime is 1100011220233. The reversal of 1100011220212 is 2120221100011.
It is a junction number, because it is equal to n+sod(n) for n = 1100011220192 and 1100011220201.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3197706864 + ... + 3197707207.
Almost surely, 21100011220212 is an apocalyptic number.
It is an amenable number.
1100011220212 is a deficient number, since it is larger than the sum of its proper divisors (869776313964).
1100011220212 is a wasteful number, since it uses less digits than its factorization.
1100011220212 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 6395414118 (or 6395414116 counting only the distinct ones).
The product of its (nonzero) digits is 16, while the sum is 13.
Adding to 1100011220212 its reverse (2120221100011), we get a palindrome (3220232320223).
The spelling of 1100011220212 in words is "one trillion, one hundred billion, eleven million, two hundred twenty thousand, two hundred twelve".
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