Base | Representation |
---|---|
bin | 11001000000101110100111… |
… | …101100111101101101000011 |
3 | 112102111000101020002000020102 |
4 | 121000232213230331231003 |
5 | 103404230000034000003 |
6 | 1025541510250033015 |
7 | 32112216542040404 |
oct | 3100564754755503 |
9 | 472430336060212 |
10 | 110001221000003 |
11 | 3206028a58a603 |
12 | 10406b8241876b |
13 | 494c0bc239278 |
14 | 1d241321799ab |
15 | cab5b69ea588 |
hex | 640ba7b3db43 |
110001221000003 has 2 divisors, whose sum is σ = 110001221000004. Its totient is φ = 110001221000002.
The previous prime is 110001220999963. The next prime is 110001221000017. The reversal of 110001221000003 is 300000122100011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 110001221000003 - 224 = 110001204222787 is a prime.
It is not a weakly prime, because it can be changed into another prime (110001221090003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55000610500001 + 55000610500002.
It is an arithmetic number, because the mean of its divisors is an integer number (55000610500002).
Almost surely, 2110001221000003 is an apocalyptic number.
110001221000003 is a deficient number, since it is larger than the sum of its proper divisors (1).
110001221000003 is an equidigital number, since it uses as much as digits as its factorization.
110001221000003 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 12, while the sum is 11.
Adding to 110001221000003 its reverse (300000122100011), we get a palindrome (410001343100014).
The spelling of 110001221000003 in words is "one hundred ten trillion, one billion, two hundred twenty-one million, three", and thus it is an aban number.
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