Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …001000011011011100110 |
3 | 10220011022210202111111222 |
4 | 100000131321003123212 |
5 | 121010311324421202 |
6 | 2201201122500342 |
7 | 142321231162622 |
oct | 20003571033346 |
9 | 3804283674458 |
10 | 1100013123302 |
11 | 3945708047a5 |
12 | 1592342046b2 |
13 | 7c966721642 |
14 | 3b353122182 |
15 | 1d931be44a2 |
hex | 1001de436e6 |
1100013123302 has 4 divisors (see below), whose sum is σ = 1650019684956. Its totient is φ = 550006561650.
The previous prime is 1100013123299. The next prime is 1100013123337. The reversal of 1100013123302 is 2033213100011.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 275003280824 + ... + 275003280827.
It is an arithmetic number, because the mean of its divisors is an integer number (412504921239).
Almost surely, 21100013123302 is an apocalyptic number.
1100013123302 is a deficient number, since it is larger than the sum of its proper divisors (550006561654).
1100013123302 is an equidigital number, since it uses as much as digits as its factorization.
1100013123302 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 550006561653.
The product of its (nonzero) digits is 108, while the sum is 17.
Adding to 1100013123302 its reverse (2033213100011), we get a palindrome (3133226223313).
The spelling of 1100013123302 in words is "one trillion, one hundred billion, thirteen million, one hundred twenty-three thousand, three hundred two".
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