1100013133231 has 4 divisors (see below), whose sum is σ = 1103550153264. Its totient is φ = 1096476113200.

The previous prime is 1100013133211. The next prime is 1100013133243. The reversal of 1100013133231 is 1323313100011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 1100013133231 - 2¹³ = 1100013125039 is a prime.

It is a super-2 number, since 2×1100013133231² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 1100013133199 and 1100013133208.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100013133211) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1768509550 + ... + 1768510171.

It is an arithmetic number, because the mean of its divisors is an integer number (275887538316).

Almost surely, 2^{1100013133231} is an apocalyptic number.

1100013133231 is a deficient number, since it is larger than the sum of its proper divisors (3537020033).

1100013133231 is an equidigital number, since it uses as much as digits as its factorization.

1100013133231 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3537020032.

The product of its (nonzero) digits is 162, while the sum is 19.

Adding to 1100013133231 its reverse (1323313100011), we get a palindrome (2423326233242).

The spelling of 1100013133231 in words is "one trillion, one hundred billion, thirteen million, one hundred thirty-three thousand, two hundred thirty-one".