1100013125039 has 2 divisors, whose sum is σ = 1100013125040. Its totient is φ = 1100013125038.

The previous prime is 1100013125033. The next prime is 1100013125153. The reversal of 1100013125039 is 9305213100011.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100013125039 is a prime.

It is a super-3 number, since 3×1100013125039³ (a number of 37 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1100013124999 and 1100013125017.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (1100013125033) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006562519 + 550006562520.

It is an arithmetic number, because the mean of its divisors is an integer number (550006562520).

Almost surely, 2^{1100013125039} is an apocalyptic number.

1100013125039 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013125039 is an equidigital number, since it uses as much as digits as its factorization.

1100013125039 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 810, while the sum is 26.

The spelling of 1100013125039 in words is "one trillion, one hundred billion, thirteen million, one hundred twenty-five thousand, thirty-nine".