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1100013231131 is a prime number
BaseRepresentation
bin10000000000011101111…
…001011101110000011011
310220011022210221222102122
4100000131321131300123
5121010311341344011
62201201125051455
7142321232122163
oct20003571356033
93804283858378
101100013231131
11394570878811
12159234256b8b
137c96675b749
143b35314d5a3
151d931c163db
hex1001de5dc1b

1100013231131 has 2 divisors, whose sum is σ = 1100013231132. Its totient is φ = 1100013231130.

The previous prime is 1100013231091. The next prime is 1100013231179. The reversal of 1100013231131 is 1311323100011.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 1100013231131 - 226 = 1099946122267 is a prime.

It is a super-2 number, since 2×11000132311312 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100013231181) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006615565 + 550006615566.

It is an arithmetic number, because the mean of its divisors is an integer number (550006615566).

Almost surely, 21100013231131 is an apocalyptic number.

1100013231131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100013231131 is an equidigital number, since it uses as much as digits as its factorization.

1100013231131 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100013231131 its reverse (1311323100011), we get a palindrome (2411336331142).

The spelling of 1100013231131 in words is "one trillion, one hundred billion, thirteen million, two hundred thirty-one thousand, one hundred thirty-one".