Base | Representation |
---|---|
bin | 10000000000011101111… |
… | …001011101110000011011 |
3 | 10220011022210221222102122 |
4 | 100000131321131300123 |
5 | 121010311341344011 |
6 | 2201201125051455 |
7 | 142321232122163 |
oct | 20003571356033 |
9 | 3804283858378 |
10 | 1100013231131 |
11 | 394570878811 |
12 | 159234256b8b |
13 | 7c96675b749 |
14 | 3b35314d5a3 |
15 | 1d931c163db |
hex | 1001de5dc1b |
1100013231131 has 2 divisors, whose sum is σ = 1100013231132. Its totient is φ = 1100013231130.
The previous prime is 1100013231091. The next prime is 1100013231179. The reversal of 1100013231131 is 1311323100011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 1100013231131 - 226 = 1099946122267 is a prime.
It is a super-2 number, since 2×11000132311312 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1100013231181) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550006615565 + 550006615566.
It is an arithmetic number, because the mean of its divisors is an integer number (550006615566).
Almost surely, 21100013231131 is an apocalyptic number.
1100013231131 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100013231131 is an equidigital number, since it uses as much as digits as its factorization.
1100013231131 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 54, while the sum is 17.
Adding to 1100013231131 its reverse (1311323100011), we get a palindrome (2411336331142).
The spelling of 1100013231131 in words is "one trillion, one hundred billion, thirteen million, two hundred thirty-one thousand, one hundred thirty-one".
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