110001343203442 has 4 divisors (see below), whose sum is σ = 165002014805166. Its totient is φ = 55000671601720.

The previous prime is 110001343203361. The next prime is 110001343203443. The reversal of 110001343203442 is 244302343100011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 56307899891881 + 53693443311561 = 7503859^2 + 7327581^2 .

It is a super-2 number, since 2×110001343203442² (a number of 29 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 110001343203442.

It is not an unprimeable number, because it can be changed into a prime (110001343203443) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 27500335800859 + ... + 27500335800862.

Almost surely, 2^{110001343203442} is an apocalyptic number.

110001343203442 is a deficient number, since it is larger than the sum of its proper divisors (55000671601724).

110001343203442 is an equidigital number, since it uses as much as digits as its factorization.

110001343203442 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 55000671601723.

The product of its (nonzero) digits is 6912, while the sum is 28.

Adding to 110001343203442 its reverse (244302343100011), we get a palindrome (354303686303453).

The spelling of 110001343203442 in words is "one hundred ten trillion, one billion, three hundred forty-three million, two hundred three thousand, four hundred forty-two".