Base | Representation |
---|---|
bin | 110011001110010100… |
… | …0010111011110110001 |
3 | 101111221020012002121202 |
4 | 1212130220113132301 |
5 | 3300241003310113 |
6 | 122311220500545 |
7 | 10642644441416 |
oct | 1463450273661 |
9 | 344836162552 |
10 | 110002010033 |
11 | 427192a32a3 |
12 | 1939b54a755 |
13 | a4b0a51a86 |
14 | 547758810d |
15 | 2cdc393258 |
hex | 199ca177b1 |
110002010033 has 2 divisors, whose sum is σ = 110002010034. Its totient is φ = 110002010032.
The previous prime is 110002010017. The next prime is 110002010059. The reversal of 110002010033 is 330010200011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107153439649 + 2848570384 = 327343^2 + 53372^2 .
It is an emirp because it is prime and its reverse (330010200011) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 110002010033 - 24 = 110002010017 is a prime.
It is a super-2 number, since 2×1100020100332 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 110002009996 and 110002010023.
It is not a weakly prime, because it can be changed into another prime (110002010003) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001005016 + 55001005017.
It is an arithmetic number, because the mean of its divisors is an integer number (55001005017).
Almost surely, 2110002010033 is an apocalyptic number.
It is an amenable number.
110002010033 is a deficient number, since it is larger than the sum of its proper divisors (1).
110002010033 is an equidigital number, since it uses as much as digits as its factorization.
110002010033 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 11.
Adding to 110002010033 its reverse (330010200011), we get a palindrome (440012210044).
The spelling of 110002010033 in words is "one hundred ten billion, two million, ten thousand, thirty-three".
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