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11000211017 is a prime number
BaseRepresentation
bin10100011111010100…
…11110011001001001
31001101121211121200212
422033222132121021
5140012023223032
65015312410505
7536411152025
oct121752363111
931347747625
1011000211017
114735372394
12216bb46a35
131063c9c703
14764d27385
15445ad1bb2
hex28fa9e649

11000211017 has 2 divisors, whose sum is σ = 11000211018. Its totient is φ = 11000211016.

The previous prime is 11000210971. The next prime is 11000211043. The reversal of 11000211017 is 71011200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 10100451001 + 899760016 = 100501^2 + 29996^2 .

It is an emirp because it is prime and its reverse (71011200011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000211017 - 26 = 11000210953 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 11000210992 and 11000211010.

It is not a weakly prime, because it can be changed into another prime (11000219017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500105508 + 5500105509.

It is an arithmetic number, because the mean of its divisors is an integer number (5500105509).

Almost surely, 211000211017 is an apocalyptic number.

It is an amenable number.

11000211017 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000211017 is an equidigital number, since it uses as much as digits as its factorization.

11000211017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 14, while the sum is 14.

Adding to 11000211017 its reverse (71011200011), we get a palindrome (82011411028).

The spelling of 11000211017 in words is "eleven billion, two hundred eleven thousand, seventeen".