Base | Representation |
---|---|
bin | 10100011111010100… |
… | …11110101000101111 |
3 | 1001101121211200001211 |
4 | 22033222132220233 |
5 | 140012023241030 |
6 | 5015312415251 |
7 | 536411154652 |
oct | 121752365057 |
9 | 31347750054 |
10 | 11000212015 |
11 | 4735373111 |
12 | 216bb47527 |
13 | 1063c9ccc0 |
14 | 764d27899 |
15 | 445ad212a |
hex | 28fa9ea2f |
11000212015 has 32 divisors (see below), whose sum is σ = 15119709696. Its totient is φ = 7610941440.
The previous prime is 11000212009. The next prime is 11000212031. The reversal of 11000212015 is 51021200011.
It is not a de Polignac number, because 11000212015 - 23 = 11000212007 is a prime.
It is a Harshad number since it is a multiple of its sum of digits (13).
It is a junction number, because it is equal to n+sod(n) for n = 11000211986 and 11000212004.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 224095 + ... + 268735.
It is an arithmetic number, because the mean of its divisors is an integer number (472490928).
Almost surely, 211000212015 is an apocalyptic number.
11000212015 is a deficient number, since it is larger than the sum of its proper divisors (4119497681).
11000212015 is a wasteful number, since it uses less digits than its factorization.
11000212015 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 44899.
The product of its (nonzero) digits is 20, while the sum is 13.
Adding to 11000212015 its reverse (51021200011), we get a palindrome (62021412026).
The spelling of 11000212015 in words is "eleven billion, two hundred twelve thousand, fifteen".
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