Base | Representation |
---|---|
bin | 1010000000010010111110… |
… | …1111011110100100010001 |
3 | 1102221121110200222120122222 |
4 | 2200010233233132210101 |
5 | 2420211413312021202 |
6 | 35221232220110425 |
7 | 2213511341055125 |
oct | 240045757364421 |
9 | 42847420876588 |
10 | 11000212220177 |
11 | 3561189029094 |
12 | 1297ab8995415 |
13 | 61a41439961b |
14 | 2a05ad819585 |
15 | 14121a1294a2 |
hex | a012fbde911 |
11000212220177 has 2 divisors, whose sum is σ = 11000212220178. Its totient is φ = 11000212220176.
The previous prime is 11000212220161. The next prime is 11000212220227. The reversal of 11000212220177 is 77102221200011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 10285111975681 + 715100244496 = 3207041^2 + 845636^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000212220177 - 24 = 11000212220161 is a prime.
It is a super-2 number, since 2×110002122201772 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (11000212220117) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500106110088 + 5500106110089.
It is an arithmetic number, because the mean of its divisors is an integer number (5500106110089).
Almost surely, 211000212220177 is an apocalyptic number.
It is an amenable number.
11000212220177 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000212220177 is an equidigital number, since it uses as much as digits as its factorization.
11000212220177 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 784, while the sum is 26.
Adding to 11000212220177 its reverse (77102221200011), we get a palindrome (88102433420188).
The spelling of 11000212220177 in words is "eleven trillion, two hundred twelve million, two hundred twenty thousand, one hundred seventy-seven".
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