11000220012221 has 4 divisors (see below), whose sum is σ = 12000240013344. Its totient is φ = 10000200011100.

The previous prime is 11000220012217. The next prime is 11000220012251. The reversal of 11000220012221 is 12221002200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000220012221 - 2² = 11000220012217 is a prime.

It is a super-3 number, since 3×11000220012221³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000220012196 and 11000220012205.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000220012251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 500010000545 + ... + 500010000566.

It is an arithmetic number, because the mean of its divisors is an integer number (3000060003336).

Almost surely, 2^{11000220012221} is an apocalyptic number.

11000220012221 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

It is an amenable number.

11000220012221 is a deficient number, since it is larger than the sum of its proper divisors (1000020001123).

11000220012221 is a wasteful number, since it uses less digits than its factorization.

11000220012221 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1000020001122.

The product of its (nonzero) digits is 32, while the sum is 14.

Adding to 11000220012221 its reverse (12221002200011), we get a palindrome (23221222212232).

The spelling of 11000220012221 in words is "eleven trillion, two hundred twenty million, twelve thousand, two hundred twenty-one".