11000221999993 has 2 divisors, whose sum is σ = 11000221999994. Its totient is φ = 11000221999992.

The previous prime is 11000221999979. The next prime is 11000222000051. The reversal of 11000221999993 is 39999912200011.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 5969944562409 + 5030277437584 = 2443347^2 + 2242828^2 .

It is an emirp because it is prime and its reverse (39999912200011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000221999993 - 2¹⁷ = 11000221868921 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000221999093) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500110999996 + 5500110999997.

It is an arithmetic number, because the mean of its divisors is an integer number (5500110999997).

Almost surely, 2^{11000221999993} is an apocalyptic number.

It is an amenable number.

11000221999993 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000221999993 is an equidigital number, since it uses as much as digits as its factorization.

11000221999993 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 708588, while the sum is 55.

The spelling of 11000221999993 in words is "eleven trillion, two hundred twenty-one million, nine hundred ninety-nine thousand, nine hundred ninety-three".