Base | Representation |
---|---|
bin | 1010000000010011000001… |
… | …0100110010011111100010 |
3 | 1102221121111101101111121012 |
4 | 2200010300110302133202 |
5 | 2420211423313013442 |
6 | 35221233205500522 |
7 | 2213511520153034 |
oct | 240046024623742 |
9 | 42847441344535 |
10 | 11000222001122 |
11 | 35611935a9712 |
12 | 1297b00111742 |
13 | 61a416412573 |
14 | 2a05b0c43c54 |
15 | 14121ae0c582 |
hex | a01305327e2 |
11000222001122 has 4 divisors (see below), whose sum is σ = 16500333001686. Its totient is φ = 5500111000560.
The previous prime is 11000222001103. The next prime is 11000222001179. The reversal of 11000222001122 is 22110022200011.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 9607588351321 + 1392633649801 = 3099611^2 + 1180099^2 .
It is a zygodrome in base 10.
It is a junction number, because it is equal to n+sod(n) for n = 11000222001097 and 11000222001106.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2750055500279 + ... + 2750055500282.
Almost surely, 211000222001122 is an apocalyptic number.
11000222001122 is a deficient number, since it is larger than the sum of its proper divisors (5500111000564).
11000222001122 is an equidigital number, since it uses as much as digits as its factorization.
11000222001122 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5500111000563.
The product of its (nonzero) digits is 32, while the sum is 14.
Adding to 11000222001122 its reverse (22110022200011), we get a palindrome (33110244201133).
The spelling of 11000222001122 in words is "eleven trillion, two hundred twenty-two million, one thousand, one hundred twenty-two".
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