Base | Representation |
---|---|
bin | 1010000000010011000001… |
… | …0101100011100010100001 |
3 | 1102221121111101202201011202 |
4 | 2200010300111203202201 |
5 | 2420211423340431032 |
6 | 35221233214050545 |
7 | 2213511521650526 |
oct | 240046025434241 |
9 | 42847441681152 |
10 | 11000222202017 |
11 | 3561193726644 |
12 | 1297b001a9a55 |
13 | 61a416482b39 |
14 | 2a05b0c9714d |
15 | 14121ae4bd62 |
hex | a01305638a1 |
11000222202017 has 2 divisors, whose sum is σ = 11000222202018. Its totient is φ = 11000222202016.
The previous prime is 11000222202001. The next prime is 11000222202031. The reversal of 11000222202017 is 71020222200011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10221167067136 + 779055134881 = 3197056^2 + 882641^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000222202017 - 24 = 11000222202001 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 11000222202017.
It is not a weakly prime, because it can be changed into another prime (11000222207017) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500111101008 + 5500111101009.
It is an arithmetic number, because the mean of its divisors is an integer number (5500111101009).
Almost surely, 211000222202017 is an apocalyptic number.
It is an amenable number.
11000222202017 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000222202017 is an equidigital number, since it uses as much as digits as its factorization.
11000222202017 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 224, while the sum is 20.
Adding to 11000222202017 its reverse (71020222200011), we get a palindrome (82020444402028).
The spelling of 11000222202017 in words is "eleven trillion, two hundred twenty-two million, two hundred two thousand, seventeen".
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