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11000223119987 is a prime number
BaseRepresentation
bin1010000000010011000001…
…1001000011101001110011
31102221121111110111100101122
42200010300121003221303
52420211424104314422
635221233245452455
72213511532523033
oct240046031035163
942847443440348
1011000223119987
1135611941a32a2
121297b0057112b
1361a41671490a
142a05b10558c3
1514121b07dd42
hexa0130643a73

11000223119987 has 2 divisors, whose sum is σ = 11000223119988. Its totient is φ = 11000223119986.

The previous prime is 11000223119983. The next prime is 11000223120017. The reversal of 11000223119987 is 78991132200011.

It is a weak prime.

It is an emirp because it is prime and its reverse (78991132200011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 11000223119987 - 22 = 11000223119983 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000223119981) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500111559993 + 5500111559994.

It is an arithmetic number, because the mean of its divisors is an integer number (5500111559994).

Almost surely, 211000223119987 is an apocalyptic number.

11000223119987 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000223119987 is an equidigital number, since it uses as much as digits as its factorization.

11000223119987 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 54432, while the sum is 44.

Adding to 11000223119987 its reverse (78991132200011), we get a palindrome (89991355319998).

The spelling of 11000223119987 in words is "eleven trillion, two hundred twenty-three million, one hundred nineteen thousand, nine hundred eighty-seven".