Base | Representation |
---|---|
bin | 1010000000010011000001… |
… | …1001110010010100001111 |
3 | 1102221121111110212001120121 |
4 | 2200010300121302110033 |
5 | 2420211424131423434 |
6 | 35221233253525411 |
7 | 2213511534250210 |
oct | 240046031622417 |
9 | 42847443761517 |
10 | 11000223311119 |
11 | 3561194313959 |
12 | 1297b00643867 |
13 | 61a416780903 |
14 | 2a05b10a5407 |
15 | 14121b0ba7b4 |
hex | a013067250f |
11000223311119 has 16 divisors (see below), whose sum is σ = 13005367441920. Its totient is φ = 9103508961120.
The previous prime is 11000223311113. The next prime is 11000223311149. The reversal of 11000223311119 is 91111332200011.
It is not a de Polignac number, because 11000223311119 - 25 = 11000223311087 is a prime.
It is a super-2 number, since 2×110002233111192 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11000223311093 and 11000223311102.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11000223311113) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 16433782 + ... + 17090044.
It is an arithmetic number, because the mean of its divisors is an integer number (812835465120).
Almost surely, 211000223311119 is an apocalyptic number.
11000223311119 is a deficient number, since it is larger than the sum of its proper divisors (2005144130801).
11000223311119 is an equidigital number, since it uses as much as digits as its factorization.
11000223311119 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 738870.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 11000223311119 in words is "eleven trillion, two hundred twenty-three million, three hundred eleven thousand, one hundred nineteen".
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