11000231213333 has 4 divisors (see below), whose sum is σ = 11007812352768. Its totient is φ = 10992650073900.

The previous prime is 11000231213303. The next prime is 11000231213351. The reversal of 11000231213333 is 33331213200011.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000231213333 - 2¹² = 11000231209237 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000231213299 and 11000231213308.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000231213303) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 3790567541 + ... + 3790570442.

It is an arithmetic number, because the mean of its divisors is an integer number (2751953088192).

Almost surely, 2^{11000231213333} is an apocalyptic number.

It is an amenable number.

11000231213333 is a deficient number, since it is larger than the sum of its proper divisors (7581139435).

11000231213333 is an equidigital number, since it uses as much as digits as its factorization.

11000231213333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7581139434.

The product of its (nonzero) digits is 972, while the sum is 23.

Adding to 11000231213333 its reverse (33331213200011), we get a palindrome (44331444413344).

The spelling of 11000231213333 in words is "eleven trillion, two hundred thirty-one million, two hundred thirteen thousand, three hundred thirty-three".