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1100023313089 is a prime number
BaseRepresentation
bin10000000000011110011…
…111111011001011000001
310220011100111221012021111
4100000132133323023001
5121010321432004324
62201202125123321
7142321413612511
oct20003637731301
93804314835244
101100023313089
11394576534508
121592376b9541
137c96887b6bc
143b354615841
151d932a58794
hex1001e7fb2c1

1100023313089 has 2 divisors, whose sum is σ = 1100023313090. Its totient is φ = 1100023313088.

The previous prime is 1100023313033. The next prime is 1100023313117. The reversal of 1100023313089 is 9803133200011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1044109981489 + 55913331600 = 1021817^2 + 236460^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100023313089 - 219 = 1100022788801 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100023313089.

It is not a weakly prime, because it can be changed into another prime (1100023313009) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550011656544 + 550011656545.

It is an arithmetic number, because the mean of its divisors is an integer number (550011656545).

Almost surely, 21100023313089 is an apocalyptic number.

It is an amenable number.

1100023313089 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100023313089 is an equidigital number, since it uses as much as digits as its factorization.

1100023313089 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3888, while the sum is 31.

The spelling of 1100023313089 in words is "one trillion, one hundred billion, twenty-three million, three hundred thirteen thousand, eighty-nine".