1100023313111 has 4 divisors (see below), whose sum is σ = 1100025803232. Its totient is φ = 1100020822992.

The previous prime is 1100023313089. The next prime is 1100023313117. The reversal of 1100023313111 is 1113133200011.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1100023313111 is a prime.

It is a super-2 number, since 2×1100023313111² (a number of 25 digits) contains 22 as substring.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 1100023313111.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (1100023313117) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 383870 + ... + 1532123.

It is an arithmetic number, because the mean of its divisors is an integer number (275006450808).

Almost surely, 2^{1100023313111} is an apocalyptic number.

1100023313111 is a deficient number, since it is larger than the sum of its proper divisors (2490121).

1100023313111 is an equidigital number, since it uses as much as digits as its factorization.

1100023313111 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2490120.

The product of its (nonzero) digits is 54, while the sum is 17.

Adding to 1100023313111 its reverse (1113133200011), we get a palindrome (2213156513122).

The spelling of 1100023313111 in words is "one trillion, one hundred billion, twenty-three million, three hundred thirteen thousand, one hundred eleven".