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11000233312130 = 251100023331213
BaseRepresentation
bin1010000000010011000011…
…1111111011111110000010
31102221121112011200011101102
42200010300333323332002
52420211434211442010
635221234252134402
72213512015252526
oct240046077737602
942847464604342
1011000233312130
113561199a24857
121297b03a67402
1361a418872a7a
142a05b2549d86
1514121bde3ba5
hexa0130ffbf82

11000233312130 has 8 divisors (see below), whose sum is σ = 19800419961852. Its totient is φ = 4400093324848.

The previous prime is 11000233312129. The next prime is 11000233312151. The reversal of 11000233312130 is 3121333200011.

11000233312130 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It can be written as a sum of positive squares in 2 ways, for example, as 9412605592009 + 1587627720121 = 3067997^2 + 1260011^2 .

It is a sphenic number, since it is the product of 3 distinct primes.

It is a Curzon number.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 550011665597 + ... + 550011665616.

Almost surely, 211000233312130 is an apocalyptic number.

11000233312130 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

11000233312130 is a deficient number, since it is larger than the sum of its proper divisors (8800186649722).

11000233312130 is a wasteful number, since it uses less digits than its factorization.

11000233312130 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1100023331220.

The product of its (nonzero) digits is 324, while the sum is 20.

Adding to 11000233312130 its reverse (3121333200011), we get a palindrome (14121566512141).

The spelling of 11000233312130 in words is "eleven trillion, two hundred thirty-three million, three hundred twelve thousand, one hundred thirty".

Divisors: 1 2 5 10 1100023331213 2200046662426 5500116656065 11000233312130