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11000253 = 311333341
BaseRepresentation
bin101001111101…
…100110111101
3202200212111210
4221331212331
510304002003
61031435033
7162333465
oct51754675
922625453
1011000253
116233720
123825a79
132381c34
141664ba5
15e74503
hexa7d9bd

11000253 has 8 divisors (see below), whose sum is σ = 16000416. Its totient is φ = 6666800.

The previous prime is 11000189. The next prime is 11000273. The reversal of 11000253 is 35200011.

It is a sphenic number, since it is the product of 3 distinct primes.

It is a cyclic number.

It is not a de Polignac number, because 11000253 - 26 = 11000189 is a prime.

It is a super-3 number, since 3×110002533 (a number of 22 digits) contains 333 as substring.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000273) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 166638 + ... + 166703.

It is an arithmetic number, because the mean of its divisors is an integer number (2000052).

Almost surely, 211000253 is an apocalyptic number.

It is an amenable number.

11000253 is a deficient number, since it is larger than the sum of its proper divisors (5000163).

11000253 is a wasteful number, since it uses less digits than its factorization.

11000253 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 333355.

The product of its (nonzero) digits is 30, while the sum is 12.

The square root of 11000253 is about 3316.6629313212. The cubic root of 11000253 is about 222.3997140953.

Adding to 11000253 its reverse (35200011), we get a palindrome (46200264).

The spelling of 11000253 in words is "eleven million, two hundred fifty-three", and thus it is an aban number.

Divisors: 1 3 11 33 333341 1000023 3666751 11000253