1100030042113 has 2 divisors, whose sum is σ = 1100030042114. Its totient is φ = 1100030042112.

The previous prime is 1100030042101. The next prime is 1100030042117. The reversal of 1100030042113 is 3112400300011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 957642302464 + 142387739649 = 978592^2 + 377343^2 .

It is an emirp because it is prime and its reverse (3112400300011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100030042113 - 2⁵ = 1100030042081 is a prime.

It is a super-2 number, since 2×1100030042113² (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1100030042117) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550015021056 + 550015021057.

It is an arithmetic number, because the mean of its divisors is an integer number (550015021057).

Almost surely, 2^{1100030042113} is an apocalyptic number.

It is an amenable number.

1100030042113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100030042113 is an equidigital number, since it uses as much as digits as its factorization.

1100030042113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 1100030042113 its reverse (3112400300011), we get a palindrome (4212430342124).

The spelling of 1100030042113 in words is "one trillion, one hundred billion, thirty million, forty-two thousand, one hundred thirteen".