11000310212013 has 4 divisors (see below), whose sum is σ = 14667080282688. Its totient is φ = 7333540141340.

The previous prime is 11000310211991. The next prime is 11000310212039. The reversal of 11000310212013 is 31021201300011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11000310212013 - 2⁸ = 11000310211757 is a prime.

It is a super-3 number, since 3×11000310212013³ (a number of 40 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 11000310211983 and 11000310212001.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000310212053) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1833385035333 + ... + 1833385035338.

It is an arithmetic number, because the mean of its divisors is an integer number (3666770070672).

Almost surely, 2^{11000310212013} is an apocalyptic number.

It is an amenable number.

11000310212013 is a deficient number, since it is larger than the sum of its proper divisors (3666770070675).

11000310212013 is an equidigital number, since it uses as much as digits as its factorization.

11000310212013 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3666770070674.

The product of its (nonzero) digits is 36, while the sum is 15.

Adding to 11000310212013 its reverse (31021201300011), we get a palindrome (42021511512024).

The spelling of 11000310212013 in words is "eleven trillion, three hundred ten million, two hundred twelve thousand, thirteen".