110003103113 has 4 divisors (see below), whose sum is σ = 110243810580. Its totient is φ = 109762395648.

The previous prime is 110003103103. The next prime is 110003103149. The reversal of 110003103113 is 311301300011.

It is a happy number.

It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 311301300011 = 13 ⋅23946253847.

It can be written as a sum of positive squares in 2 ways, for example, as 91259576464 + 18743526649 = 302092^2 + 136907^2 .

It is a cyclic number.

It is not a de Polignac number, because 110003103113 - 2⁸ = 110003102857 is a prime.

It is a super-3 number, since 3×110003103113³ (a number of 34 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (110003103103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 120353048 + ... + 120353961.

It is an arithmetic number, because the mean of its divisors is an integer number (27560952645).

Almost surely, 2^110003103113 is an apocalyptic number.

It is an amenable number.

110003103113 is a deficient number, since it is larger than the sum of its proper divisors (240707467).

110003103113 is an equidigital number, since it uses as much as digits as its factorization.

110003103113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 240707466.

The product of its (nonzero) digits is 27, while the sum is 14.

Adding to 110003103113 its reverse (311301300011), we get a palindrome (421304403124).

It can be divided in two parts, 11000 and 3103113, that added together give a palindrome (3114113).

The spelling of 110003103113 in words is "one hundred ten billion, three million, one hundred three thousand, one hundred thirteen".