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110003103112 = 2372280620161
BaseRepresentation
bin110011001110010110…
…0100010010110001000
3101111221022020122001011
41212130230202112020
53300241243244422
6122311300133304
710642656643300
oct1463454422610
9344838218034
10110003103112
114271997a571
121939b997234
13a4b1045476
145477790600
152cdc50c077
hex199cb22588

110003103112 has 24 divisors (see below), whose sum is σ = 239930238510. Its totient is φ = 47144186880.

The previous prime is 110003103103. The next prime is 110003103149. The reversal of 110003103112 is 211301300011.

It can be written as a sum of positive squares in only one way, i.e., 85377333636 + 24625769476 = 292194^2 + 156926^2 .

It is a super-3 number, since 3×1100031031123 (a number of 34 digits) contains 333 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 110003103092 and 110003103101.

It is an unprimeable number.

It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 140309689 + ... + 140310472.

Almost surely, 2110003103112 is an apocalyptic number.

It is an amenable number.

110003103112 is an abundant number, since it is smaller than the sum of its proper divisors (129927135398).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

110003103112 is a wasteful number, since it uses less digits than its factorization.

110003103112 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 280620181 (or 280620170 counting only the distinct ones).

The product of its (nonzero) digits is 18, while the sum is 13.

Adding to 110003103112 its reverse (211301300011), we get a palindrome (321304403123).

The spelling of 110003103112 in words is "one hundred ten billion, three million, one hundred three thousand, one hundred twelve".

Divisors: 1 2 4 7 8 14 28 49 56 98 196 392 280620161 561240322 1122480644 1964341127 2244961288 3928682254 7857364508 13750387889 15714729016 27500775778 55001551556 110003103112