Base | Representation |
---|---|
bin | 10000000000011110111… |
… | …101101011001111101011 |
3 | 10220011101001121102121101 |
4 | 100000132331223033223 |
5 | 121010330431042141 |
6 | 2201203004222231 |
7 | 142321540114405 |
oct | 20003675531753 |
9 | 3804331542541 |
10 | 1100031112171 |
11 | 39457a981032 |
12 | 15923a23a977 |
13 | 7c96a37c544 |
14 | 3b355685b75 |
15 | 1d933599531 |
hex | 1001ef6b3eb |
1100031112171 has 2 divisors, whose sum is σ = 1100031112172. Its totient is φ = 1100031112170.
The previous prime is 1100031112057. The next prime is 1100031112231. The reversal of 1100031112171 is 1712111300011.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1100031112171 - 213 = 1100031103979 is a prime.
It is a super-3 number, since 3×11000311121713 (a number of 37 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (1100031115171) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550015556085 + 550015556086.
It is an arithmetic number, because the mean of its divisors is an integer number (550015556086).
Almost surely, 21100031112171 is an apocalyptic number.
1100031112171 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100031112171 is an equidigital number, since it uses as much as digits as its factorization.
1100031112171 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 42, while the sum is 19.
Adding to 1100031112171 its reverse (1712111300011), we get a palindrome (2812142412182).
The spelling of 1100031112171 in words is "one trillion, one hundred billion, thirty-one million, one hundred twelve thousand, one hundred seventy-one".
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