Base | Representation |
---|---|
bin | 10100011111010101… |
… | …10110111000010000 |
3 | 1001101122000201021111 |
4 | 22033222312320100 |
5 | 140012034430222 |
6 | 5015314503104 |
7 | 536412050314 |
oct | 121752667020 |
9 | 31348021244 |
10 | 11000311312 |
11 | 4735430781 |
12 | 216bb94a94 |
13 | 1064006263 |
14 | 764d51b44 |
15 | 445b01777 |
hex | 28fab6e10 |
11000311312 has 40 divisors (see below), whose sum is σ = 23294794752. Its totient is φ = 5009625600.
The previous prime is 11000311303. The next prime is 11000311351. The reversal of 11000311312 is 21311300011.
11000311312 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a super-3 number, since 3×110003113123 (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is a junction number, because it is equal to n+sod(n) for n = 11000311292 and 11000311301.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 643864 + ... + 660727.
Almost surely, 211000311312 is an apocalyptic number.
It is an amenable number.
11000311312 is an abundant number, since it is smaller than the sum of its proper divisors (12294483440).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
11000311312 is a wasteful number, since it uses less digits than its factorization.
11000311312 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1304647 (or 1304641 counting only the distinct ones).
The product of its (nonzero) digits is 18, while the sum is 13.
Adding to 11000311312 its reverse (21311300011), we get a palindrome (32311611323).
The spelling of 11000311312 in words is "eleven billion, three hundred eleven thousand, three hundred twelve".
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