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110003113387 is a prime number
BaseRepresentation
bin110011001110010110…
…0100100110110101011
3101111221022021011010201
41212130230210312223
53300241244112022
6122311300253031
710642660015246
oct1463454446653
9344838234121
10110003113387
1142719987262
121939b9a1177
13a4b104a04b
14547779425d
152cdc510127
hex199cb24dab

110003113387 has 2 divisors, whose sum is σ = 110003113388. Its totient is φ = 110003113386.

The previous prime is 110003113303. The next prime is 110003113411. The reversal of 110003113387 is 783311300011.

It is a strong prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110003113387 is a prime.

It is a super-3 number, since 3×1100031133873 (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (110003114387) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55001556693 + 55001556694.

It is an arithmetic number, because the mean of its divisors is an integer number (55001556694).

Almost surely, 2110003113387 is an apocalyptic number.

110003113387 is a deficient number, since it is larger than the sum of its proper divisors (1).

110003113387 is an equidigital number, since it uses as much as digits as its factorization.

110003113387 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 28.

Adding to 110003113387 its reverse (783311300011), we get a palindrome (893314413398).

The spelling of 110003113387 in words is "one hundred ten billion, three million, one hundred thirteen thousand, three hundred eighty-seven".