11000330000311 has 4 divisors (see below), whose sum is σ = 11000512635624. Its totient is φ = 11000147365000.

The previous prime is 11000330000299. The next prime is 11000330000339. The reversal of 11000330000311 is 11300003300011.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 11000330000311 - 2⁵ = 11000330000279 is a prime.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11000330000291 and 11000330000300.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000330000411) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 91227280 + ... + 91347781.

It is an arithmetic number, because the mean of its divisors is an integer number (2750128158906).

Almost surely, 2^{11000330000311} is an apocalyptic number.

11000330000311 is a deficient number, since it is larger than the sum of its proper divisors (182635313).

11000330000311 is an equidigital number, since it uses as much as digits as its factorization.

11000330000311 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 182635312.

The product of its (nonzero) digits is 27, while the sum is 13.

Adding to 11000330000311 its reverse (11300003300011), we get a palindrome (22300333300322).

The spelling of 11000330000311 in words is "eleven trillion, three hundred thirty million, three hundred eleven", and thus it is an aban number.