1100033912137 has 2 divisors, whose sum is σ = 1100033912138. Its totient is φ = 1100033912136.

The previous prime is 1100033912123. The next prime is 1100033912141. The reversal of 1100033912137 is 7312193300011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1020819246736 + 79214665401 = 1010356^2 + 281451^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100033912137 - 2²⁷ = 1099899694409 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1100033912099 and 1100033912108.

It is not a weakly prime, because it can be changed into another prime (1100033912437) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550016956068 + 550016956069.

It is an arithmetic number, because the mean of its divisors is an integer number (550016956069).

Almost surely, 2^{1100033912137} is an apocalyptic number.

It is an amenable number.

1100033912137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100033912137 is an equidigital number, since it uses as much as digits as its factorization.

1100033912137 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 3402, while the sum is 31.

The spelling of 1100033912137 in words is "one trillion, one hundred billion, thirty-three million, nine hundred twelve thousand, one hundred thirty-seven".