11000352403350 has 288 divisors, whose sum is σ = 31375159343424. Its totient is φ = 2757406924800.

The previous prime is 11000352403309. The next prime is 11000352403357. The reversal of 11000352403350 is 5330425300011.

11000352403350 is a `hidden beast` number, since 1 + 100 + 0 + 3 + 524 + 0 + 3 + 35 + 0 = 666.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11000352403357) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written in 143 ways as a sum of consecutive naturals, for example, 209261070 + ... + 209313630.

It is an arithmetic number, because the mean of its divisors is an integer number (108941525498).

Almost surely, 2^{11000352403350} is an apocalyptic number.

11000352403350 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 11000352403350, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15687579671712).

11000352403350 is an abundant number, since it is smaller than the sum of its proper divisors (20374806940074).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

11000352403350 is a wasteful number, since it uses less digits than its factorization.

11000352403350 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 52952 (or 52944 counting only the distinct ones).

The product of its (nonzero) digits is 5400, while the sum is 27.

Adding to 11000352403350 its reverse (5330425300011), we get a palindrome (16330777703361).

The spelling of 11000352403350 in words is "eleven trillion, three hundred fifty-two million, four hundred three thousand, three hundred fifty".