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110004222000241 is a prime number
BaseRepresentation
bin11001000000110001011010…
…100100110111110001110001
3112102111022010100222121122101
4121000301122210313301301
5103404302121313001431
61025543124131540401
732112354112110262
oct3100613244676161
9472438110877571
10110004222000241
113206158a573498
121040767b45a701
13494c479bb0b5a
141d24338962969
15cab6e01da961
hex640c5a937c71

110004222000241 has 2 divisors, whose sum is σ = 110004222000242. Its totient is φ = 110004222000240.

The previous prime is 110004222000143. The next prime is 110004222000289. The reversal of 110004222000241 is 142000222400011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73377469584225 + 36626752416016 = 8566065^2 + 6052004^2 .

It is an emirp because it is prime and its reverse (142000222400011) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-110004222000241 is a prime.

It is not a weakly prime, because it can be changed into another prime (110004222060241) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55002111000120 + 55002111000121.

It is an arithmetic number, because the mean of its divisors is an integer number (55002111000121).

Almost surely, 2110004222000241 is an apocalyptic number.

It is an amenable number.

110004222000241 is a deficient number, since it is larger than the sum of its proper divisors (1).

110004222000241 is an equidigital number, since it uses as much as digits as its factorization.

110004222000241 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 256, while the sum is 19.

Adding to 110004222000241 its reverse (142000222400011), we get a palindrome (252004444400252).

The spelling of 110004222000241 in words is "one hundred ten trillion, four billion, two hundred twenty-two million, two hundred forty-one", and thus it is an aban number.