11000433120403 has 2 divisors, whose sum is σ = 11000433120404. Its totient is φ = 11000433120402.

The previous prime is 11000433120353. The next prime is 11000433120409. The reversal of 11000433120403 is 30402133400011.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 11000433120403 - 2¹³ = 11000433112211 is a prime.

It is not a weakly prime, because it can be changed into another prime (11000433120409) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500216560201 + 5500216560202.

It is an arithmetic number, because the mean of its divisors is an integer number (5500216560202).

Almost surely, 2^{11000433120403} is an apocalyptic number.

11000433120403 is a deficient number, since it is larger than the sum of its proper divisors (1).

11000433120403 is an equidigital number, since it uses as much as digits as its factorization.

11000433120403 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 864, while the sum is 22.

Adding to 11000433120403 its reverse (30402133400011), we get a palindrome (41402566520414).

The spelling of 11000433120403 in words is "eleven trillion, four hundred thirty-three million, one hundred twenty thousand, four hundred three".