Base | Representation |
---|---|
bin | 10000000000011111101… |
… | …100101000001100101001 |
3 | 10220011101220202202101211 |
4 | 100000133230220030221 |
5 | 121010342103423312 |
6 | 2201204124113121 |
7 | 142322046536542 |
oct | 20003754501451 |
9 | 3804356682354 |
10 | 1100043420457 |
11 | 394586918473 |
12 | 1592423957a1 |
13 | 7c96ca9b957 |
14 | 3b35716b4c9 |
15 | 1d9346cb3a7 |
hex | 1001fb28329 |
1100043420457 has 2 divisors, whose sum is σ = 1100043420458. Its totient is φ = 1100043420456.
The previous prime is 1100043420409. The next prime is 1100043420491. The reversal of 1100043420457 is 7540243400011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 681872971536 + 418170448921 = 825756^2 + 646661^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1100043420457 is a prime.
It is not a weakly prime, because it can be changed into another prime (1100043420757) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550021710228 + 550021710229.
It is an arithmetic number, because the mean of its divisors is an integer number (550021710229).
Almost surely, 21100043420457 is an apocalyptic number.
It is an amenable number.
1100043420457 is a deficient number, since it is larger than the sum of its proper divisors (1).
1100043420457 is an equidigital number, since it uses as much as digits as its factorization.
1100043420457 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 13440, while the sum is 31.
Adding to 1100043420457 its reverse (7540243400011), we get a palindrome (8640286820468).
The spelling of 1100043420457 in words is "one trillion, one hundred billion, forty-three million, four hundred twenty thousand, four hundred fifty-seven".
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