1100054998313 has 2 divisors, whose sum is σ = 1100054998314. Its totient is φ = 1100054998312.

The previous prime is 1100054998283. The next prime is 1100054998321. The reversal of 1100054998313 is 3138994500011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 791544737344 + 308510260969 = 889688^2 + 555437^2 .

It is a cyclic number.

It is not a de Polignac number, because 1100054998313 - 2¹² = 1100054994217 is a prime.

It is a Sophie Germain prime.

It is a Curzon number.

It is not a weakly prime, because it can be changed into another prime (1100054998213) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (13) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550027499156 + 550027499157.

It is an arithmetic number, because the mean of its divisors is an integer number (550027499157).

Almost surely, 2^{1100054998313} is an apocalyptic number.

It is an amenable number.

1100054998313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100054998313 is an equidigital number, since it uses as much as digits as its factorization.

1100054998313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 116640, while the sum is 44.

The spelling of 1100054998313 in words is "one trillion, one hundred billion, fifty-four million, nine hundred ninety-eight thousand, three hundred thirteen".