Base | Representation |
---|---|
bin | 1010000000010101111010… |
… | …1100100111100111111001 |
3 | 1102221200111121022221102012 |
4 | 2200011132230213213321 |
5 | 2420220021444444433 |
6 | 35221442321015305 |
7 | 2213540015064233 |
oct | 240053654474771 |
9 | 42850447287365 |
10 | 11000999999993 |
11 | 3561552782793 |
12 | 1298098784535 |
13 | 61a50b661223 |
14 | 2a06462c3253 |
15 | 14126438a848 |
hex | a015eb279f9 |
11000999999993 has 2 divisors, whose sum is σ = 11000999999994. Its totient is φ = 11000999999992.
The previous prime is 11000999999987. The next prime is 11001000000007. The reversal of 11000999999993 is 39999999900011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 7791645987904 + 3209354012089 = 2791352^2 + 1791467^2 .
It is a cyclic number.
It is not a de Polignac number, because 11000999999993 - 230 = 10999926258169 is a prime.
It is not a weakly prime, because it can be changed into another prime (11000999399993) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500499999996 + 5500499999997.
It is an arithmetic number, because the mean of its divisors is an integer number (5500499999997).
Almost surely, 211000999999993 is an apocalyptic number.
It is an amenable number.
11000999999993 is a deficient number, since it is larger than the sum of its proper divisors (1).
11000999999993 is an equidigital number, since it uses as much as digits as its factorization.
11000999999993 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 129140163, while the sum is 77.
The spelling of 11000999999993 in words is "eleven trillion, nine hundred ninety-nine million, nine hundred ninety-nine thousand, nine hundred ninety-three".
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