1100100000113 has 2 divisors, whose sum is σ = 1100100000114. Its totient is φ = 1100100000112.

The previous prime is 1100100000031. The next prime is 1100100000163. The reversal of 1100100000113 is 3110000010011.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1099996123249 + 103876864 = 1048807^2 + 10192^2 .

It is an emirp because it is prime and its reverse (3110000010011) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1100100000113 - 2³⁰ = 1099026258289 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 1100100000113.

It is not a weakly prime, because it can be changed into another prime (1100100000163) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 550050000056 + 550050000057.

It is an arithmetic number, because the mean of its divisors is an integer number (550050000057).

Almost surely, 2^{1100100000113} is an apocalyptic number.

It is an amenable number.

1100100000113 is a deficient number, since it is larger than the sum of its proper divisors (1).

1100100000113 is an equidigital number, since it uses as much as digits as its factorization.

1100100000113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 3, while the sum is 8.

Adding to 1100100000113 its reverse (3110000010011), we get a palindrome (4210100010124).

The spelling of 1100100000113 in words is "one trillion, one hundred billion, one hundred million, one hundred thirteen", and thus it is an aban number.