Base | Representation |
---|---|
bin | 11001000000110110110010… |
… | …111110100100101011110001 |
3 | 112102111212001001111111112011 |
4 | 121000312302332210223301 |
5 | 103404400440011200311 |
6 | 1025545521340402521 |
7 | 32112650233126354 |
oct | 3100666276445361 |
9 | 472455031444464 |
10 | 110010000100081 |
11 | 32063a85113414 |
12 | 10408812546441 |
13 | 494cb8acc5343 |
14 | 1d247260cc29b |
15 | cab92c5e0321 |
hex | 640db2fa4af1 |
110010000100081 has 2 divisors, whose sum is σ = 110010000100082. Its totient is φ = 110010000100080.
The previous prime is 110010000100069. The next prime is 110010000100103. The reversal of 110010000100081 is 180001000010011.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 107818297506481 + 2191702593600 = 10383559^2 + 1480440^2 .
It is a cyclic number.
It is not a de Polignac number, because 110010000100081 - 29 = 110010000099569 is a prime.
It is a super-2 number, since 2×1100100001000812 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (110010000100031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005000050040 + 55005000050041.
It is an arithmetic number, because the mean of its divisors is an integer number (55005000050041).
Almost surely, 2110010000100081 is an apocalyptic number.
It is an amenable number.
110010000100081 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010000100081 is an equidigital number, since it uses as much as digits as its factorization.
110010000100081 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8, while the sum is 13.
Adding to 110010000100081 its reverse (180001000010011), we get a palindrome (290011000110092).
The spelling of 110010000100081 in words is "one hundred ten trillion, ten billion, one hundred thousand, eighty-one".
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