Base | Representation |
---|---|
bin | 11001000000110110110011… |
… | …000010110001001111010011 |
3 | 112102111212001010120101102222 |
4 | 121000312303002301033103 |
5 | 103404400440301400313 |
6 | 1025545521420131255 |
7 | 32112650245360355 |
oct | 3100666302611723 |
9 | 472455033511388 |
10 | 110010001200083 |
11 | 32063a857a4906 |
12 | 10408812996b2b |
13 | 494cb8b2bbc2a |
14 | 1d247262d70d5 |
15 | cab92c75b208 |
hex | 640db30b13d3 |
110010001200083 has 2 divisors, whose sum is σ = 110010001200084. Its totient is φ = 110010001200082.
The previous prime is 110010001200079. The next prime is 110010001200133. The reversal of 110010001200083 is 380002100010011.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 110010001200083 - 22 = 110010001200079 is a prime.
It is not a weakly prime, because it can be changed into another prime (110010001200013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 55005000600041 + 55005000600042.
It is an arithmetic number, because the mean of its divisors is an integer number (55005000600042).
Almost surely, 2110010001200083 is an apocalyptic number.
110010001200083 is a deficient number, since it is larger than the sum of its proper divisors (1).
110010001200083 is an equidigital number, since it uses as much as digits as its factorization.
110010001200083 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 48, while the sum is 17.
Adding to 110010001200083 its reverse (380002100010011), we get a palindrome (490012101210094).
The spelling of 110010001200083 in words is "one hundred ten trillion, ten billion, one million, two hundred thousand, eighty-three".
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