Base | Representation |
---|---|
bin | 10100011111011010… |
… | …11111000100011001 |
3 | 1001101200022201021111 |
4 | 22033231133010121 |
5 | 140012224001332 |
6 | 5015341340321 |
7 | 536420646634 |
oct | 121755370431 |
9 | 31350281244 |
10 | 11001000217 |
11 | 4735861319 |
12 | 21702676a1 |
13 | 10641b79ac |
14 | 765090c1b |
15 | 445bda947 |
hex | 28fb5f119 |
11001000217 has 2 divisors, whose sum is σ = 11001000218. Its totient is φ = 11001000216.
The previous prime is 11001000191. The next prime is 11001000221. The reversal of 11001000217 is 71200010011.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10967116176 + 33884041 = 104724^2 + 5821^2 .
It is a cyclic number.
It is not a de Polignac number, because 11001000217 - 215 = 11000967449 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 11001000197 and 11001000206.
It is not a weakly prime, because it can be changed into another prime (11001000317) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5500500108 + 5500500109.
It is an arithmetic number, because the mean of its divisors is an integer number (5500500109).
Almost surely, 211001000217 is an apocalyptic number.
It is an amenable number.
11001000217 is a deficient number, since it is larger than the sum of its proper divisors (1).
11001000217 is an equidigital number, since it uses as much as digits as its factorization.
11001000217 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 14, while the sum is 13.
Adding to 11001000217 its reverse (71200010011), we get a palindrome (82201010228).
The spelling of 11001000217 in words is "eleven billion, one million, two hundred seventeen", and thus it is an aban number.
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